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-3x^2+6x+297=0
a = -3; b = 6; c = +297;
Δ = b2-4ac
Δ = 62-4·(-3)·297
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-60}{2*-3}=\frac{-66}{-6} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+60}{2*-3}=\frac{54}{-6} =-9 $
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